if the focal length of objective and eye piece are 1cm and 5cm.if the distance between objective and eyepiece is 25cm and final image is formed at least distant of distinct vision then the distance of object from objective lens is
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Explanation:
f0=1cm
fe=5cm
v0=1.1cm
ve=25cm
M=?
M=u0v0(1+feD)
v01−(−1.1)1=11
v0=11cm
M=1.111(1+5255)=6×10=60
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