Question

if the following figure quadrilateral ABCD is drawn to circumscribe a circle prove that AB+CD =AD + BC

Answer 1

hope it helps u........:)

Answer 2

It can be observed that

DR = DS (Tangents on the circle from point D).........(1)

CR = CQ (Tangents on the circle from point C).........(2)

BP = BQ (Tangents on the circle from point B)........(3)

AP = AS (Tangents on the circle from point A)..........(4)

Adding all these equations, we obtain

DR + CR + BP + AP = DS + CQ + BQ + AS

(DR + CR) + (BP + AP) = (DS + AS) + (CQ + BQ)

CD + AB = AD + BC