Chemistry, asked by archana2443, 1 year ago

If the following half cells have E° values as
A^{3+} + e^- \longrightarrow A^{2+}, E^0 = y_2V
A^{2+} + 2e^- \longrightarrow A, E^0 = -y_1V
The E° of the half cell A^{3+} + 3e \longrightarrow A will be
(a) \frac{2y_1 - y_2}{3}
(b) \frac{y_2 - 2y_1}{3}
(c) 2y₁ – 3y₂
(d) y₂ – 2y₁

Answers

Answered by Kashish236448
2

C is correct.

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