Question

if the following two straight line are parallel then find the value of k. 3x-3(k+1)y=2 and (k-1)x+y=4. plz solve this i will mark as brainlist.​

Answer 1

Answer:

k = 0

Step-by-step explanation:

Find the slopes of both the equation i.e. make the line of y = mx + c

x-3(k+1)y=2

3(k+1)y = x - 2

y = [3/3(k+1)]x - 2/3(k+1)

====> slope of this line 1/(k+1)

(k-1)x+y=4

y = -(k-1)x + 4

===> slope of this line = 1-k

Since both are parallel lines, the slopes will be equal.

1/(k+1) = 1-k

(1+k)(1-k) = 1

(1 - k²) = 1

k² = 0 => k = 0.