If the force applied had acted for a duration of 2 s, what will be the Angular Velocity of wheel at the end of 2 s
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Proper question:
A wheel rotates with the constant acceleration of 2.0 rad/s, if the wheel starts from rest the number of revolution it makes in first ten seconds will be approximately ?
Solution:
For circular angular motion, the formula for angular displacement θ and angular acceleration α is
θ=ωt+ 1/2 at²
θ = 0 × t + 1/2 × 2 × (10) ²
θ = 100
As acceleration is constant so velocity is zero
θ=100 radians
2π radian are covered in 1 revolution.
Thus, 100 radian is covered is covered in 100/2π revolution
Therefore,
Number of revolution = 100/2π
Number of revolution = 50/π = 15.9 ≈ 16
Required answer:
Thus, number of revolution is 16 in first ten seconds
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