Math, asked by Puja7734, 1 year ago

If the force experienced by a positively charged balloon is 2.7 newtons and the electric field strength is 7.8 × 105 newtons/coulomb, what is the magnitude of the charge on the balloon

Answers

Answered by pinquancaro
0

Since, it is given that the force experienced by a positively charged balloon is 2.7 newtons and the electric field strength is 7.8 \times 10^5newtons/coulomb.

We have to determine the magnitude of the charge on the balloon.

The relationship between electric field strength, magnitude and force is given by the formula F = qE where 'F' is the force, 'E' is the electric field intensity and 'q' is the magnitude of the charge.

Since, F = qE

2.7 = q \times 7.8 \times 10^5

q = \frac{2.7}{7.8 \times 10^5}

q = 0.35 \times 10^{-5}

Therefore, the magnitude of the charge on the balloon is 0.35 \times 10^{-5} Coulomb.


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