Question

If the force of 250 n acts on the body the momentumrequiredis125m/stheperiodforwhichtheforceactsonthebodyis

Answer 1

Answer:

Given:

Force experienced = 250N

Momentum gained = 125 m/s

To find:

Time for which force acted on the body.

Concept:

Force is defined as the rate of change of momentum. Mathematically it is represented as

F = ∆P/∆T

F is force, ∆ represents "change" , P is momentum and T is time.

Calculation:

As per the above equation,

F = ∆P/∆T

=> 250 = 125/∆T

=> ∆T = 125/250

=> ∆T = ½ seconds.

So the force acted for ½ seconds on the body.

Answer 2

♦ Question :-

If the force of 250 N acts on a body the momentum required is 125 m/s the period for which the force acts on the body is -

♦ Answer :-

$\red{ \leadsto} \boxed{\Delta \: \blue{ T \: }= \green{0.5 \: }s} \:$

♦ To find :-

→ Time period .

♦Formula used :-

$\red{\leadsto } \green{ \boxed{F \red{ \: = } \orange{ \frac{ \Delta P \: }{ \Delta \: T }} }}$

♦Explanation :-

Given that

→ Force ( F ) = 250 N

→ change in momentum ∆P = 125 m/s

according to the given formula,

$\red{\leadsto } \green{ {F \red{ \: = } \orange{ \frac{ \Delta P \: }{ \Delta \: T }} }}\\ \\ \green{ \leadsto} \: \pink{ 250} = \blue{ \frac{125}{ \red{ \Delta T \: \: }} } \\ \\ \leadsto \purple{ \Delta \: T \: } = \red{ \frac{125}{250} } \\ \\ \purple{\leadsto }\: \Delta \green{ T \: } = \blue{ \frac{1}{2} } \\ \\ \red{ \leadsto} \boxed{\Delta \: \blue{ T \: }= \green{0.5 \: }s}$

Required period is 0.5 seconds .