If the force of attraction between the earth and a body of mass 'm' is 9 * 10^7 ,what would be the value of mass' m ' ? given G= 7.6 * 10^-11 Nm^2/Kg^2 , radius of the earth , R = 6.4 * 10^6 m , mass of the earth = 6.4 * 10^24 Kg. .... plzzz helpppppppp ......
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3
given , force of gravitation ( F ) = 9 * 10^7 N
mass of the earth = 6 * 10^ 22 kg
G = 6.7 * 10^-11 Nm^2 per kg
R = 6.4 * 10^6m ,
m = ?
[tex]F = G \frac{M * m}{r^2 } m = \frac{F*R/G* M} m = 9 * 10 ^7 * (6.4 * 10^6)^2 / 6.7 * 10^-11 * 6 * 10^22 m = 9.17 * 10^6 kg [/tex]
mass of the earth = 6 * 10^ 22 kg
G = 6.7 * 10^-11 Nm^2 per kg
R = 6.4 * 10^6m ,
m = ?
[tex]F = G \frac{M * m}{r^2 } m = \frac{F*R/G* M} m = 9 * 10 ^7 * (6.4 * 10^6)^2 / 6.7 * 10^-11 * 6 * 10^22 m = 9.17 * 10^6 kg [/tex]
Answered by
2
Mass of body=7.58×10^6kg
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