Question

If the force of electric field on 5 C charge is 10 N the intensity of the field is

Answer 1

Answer:

we know F=qE here F=10 N q= 5C

so E= 10 / 5 . E= 2 N/C

Answer 2

Explanation:

Given Charge = 5C

Force = 10 N

To find Electric field intensity

using E = F/C

= 10N/5C

=2N/C