Question

If the force of F = (2i - 4j – 3k) N acting on a body pivoted at 2m
from the axis of rotation along X-axis. Then the magnitude of torque
is:
12 Nm
b. 10 Nm
c. 8 Nm
d. 6 Nm

Answer 1

Explanation:

a 12Nm mark as brainlist

Answer 2

Answer:

i think answer will be 8Nm