Question

If the force on a rocket moving in gravity free space with an exhaust velocity of gases 500 ms–1 is 250 N, then the rate of combustion of the fuel is :-​

Answer 1

Explanation:

F = ( dm / dt ) × v

250 = ( dm / dt ) × 500

( dm / dt ) = 250 / 500 = 0.5 kg/s

Answer 2

Answer: 0.5kg/s

Explanation:

We know that F=$v\frac{-dm}{dt}$.

or, 250=500$\frac{-dm}{dt}$

or $\frac{-dm}{dt}$=$\frac{250}{500}=\frac{1}{2} =0.5$ kg/s

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