Question

If the force on a rocket moving with a velocity of 300 m/sec
is 345 N, then the rate of combustion of the fuel, is​

Answer 1

Answer:

hey mate your answer is...

Explanation:

$f = \frac{dm}{dv} \\ = \frac{345}{300} \\ = 1.15kg...... \\ hope \: its \: helps....$