if the four digit number p72q is exactly divisible by9 then the least value of (p+q) is
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Question
If the 4 digit number x27y is exactly divisible by 9, then the least value of (x + y) is:
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Official Soldier Clerk Paper : [Arty Centre, Hyderabad (Che)] - 28 Feb 2021
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0
6
9
3
Answer (Detailed Solution Below)
Option 3 : 9
Detailed Solution
Given:
The 4 digit number x27y is exactly divisible by 9,
Concept Used:
If the number is divisible by 9 so sum of the number is also divisible by 9
Calculation:
x27y is exactly divisible by 9
The sum of its digits must be divisible by 9
x + 2 + 7 + y = x + y + 9 is divisible by 9
Minimum value x + y must be equal to 9 because then the sum will be 18 and it is divisible by 9.
∴ The least value of (x + y) is 9
Additional Information
The possible value of x and y can be
x = 9, y = 0
x = 1, y = 8
x = 2, y = 7
x = 3, y = 6
x = 4, y = 5
x = 5, y = 4
x = 6, y = 3
x = 7, y = 2
x = 8, y = 1
Step-by-step explanation:
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Answer:
We know that if sum of digits of a number is divisible by 9, then the number is divisible by 9. Here, x + 2 + 7 + y = multiple of 9 x + y + 9= 0, 9, 18, … Hence, x + y + 9 = 9 ∴ x + y =0 But x + y cannot be 0 because then x and y both will have to be 0.Since x is the first digit, it cannot be 0.∴ x + y + 9 = 18 x + y = 9 ∴ the least value of (x + y) is 9Read more on Sarthaks.com - https://www.sarthaks.com/1112208/if-the-4-digit-number-x27y-is-exactly-divisible-by-9-then-the-least-value-of-x-y-is-a-0-b-3-c-6?show=1112209#a1112209