If the four digit number x27y is exactly divisible by 9 then the least value of x+y=? also find the possible value of x and y
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if you know the divisibility of 9 then this question will be easy for u....
divisibility of 9 says if the sum of all the digit of number is divisible by 9 then that number will also divisible by 9.
therefore some of digit of x27y is 9+x+y
minimum value x+y must be be equal to 9 because then the sum will be 18..and it is divisible by 9.
possible value of x and y
x=9 y=0
x=1 y=8
x=2 y=7
x=3 y=6
x=4 y=5
x=5 y=4
x=6 y=3
x=7 y=2
x=8 y=1
divisibility of 9 says if the sum of all the digit of number is divisible by 9 then that number will also divisible by 9.
therefore some of digit of x27y is 9+x+y
minimum value x+y must be be equal to 9 because then the sum will be 18..and it is divisible by 9.
possible value of x and y
x=9 y=0
x=1 y=8
x=2 y=7
x=3 y=6
x=4 y=5
x=5 y=4
x=6 y=3
x=7 y=2
x=8 y=1
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if the four digit number x 27 y exactly divisible by 9. then the least value of aramark x + Y arrow mark is
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