If the four numbers are in the ratio 2:3:7:4 and their sum is 48, then find these four
numbers.
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Answer:
ratio=2:3:7:4
let the ratio be = 2x:3x:7x:4x
sum of the ratio=2x+3x+7x+4x=16x
the sum of four numbers =48
therefore 2x=2/16×48=6
3x=3/16×28=9
7x=7/16×48=21
4x=4/16×48=12
therefore the four numbers are 6,9,21,12
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