if the four term of an ap is thrice the first term and the second term exceeds twice the third term by 1 find a and d
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given: a4=3(a1); a2+1=2(a3)
a2+1=2(a3)
a+d+1=2(a+2d)
a+d+1=2a+4d
-3d+1=a..........1
a4=3(a1)
a+3d=3a
2a=3d
2(-3d+1)=3d
-6d+2=3d
2=9d
d=2/9
subs d in 1
-3d+1=a
-3(2/9)+1=a
a=-2/3+1
a=(-2+3)/3
a=1/3
hope it helps u....^_^
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