if the fourteenth term of an ap be 6 and 6th term be14 find its 20th term
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a14=a+13d
a+13d=6
a6=a+5d
a+5d=14
Now,
From the above equations
a=6-13d
in the second equation
(6-13d)+5d=14
-13d+5d=14-6
-8d=8
a=6-13(-1)
a=13+6
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