If the freeing point of thermoneter is 20 and boilind point is is 150 so how 60 will be read in thermometer
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0
et x = reading of new thermometer ,
then,
( x - 20)/(150-20) = C/100
(x -20)/13 = C/10
( x -20)/13 = 60/10 = 6
x -20 = 78
x = 98
then,
( x - 20)/(150-20) = C/100
(x -20)/13 = C/10
( x -20)/13 = 60/10 = 6
x -20 = 78
x = 98
Answered by
1
Answer:
98
Explanation:
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