If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex(which
behaves as a strong electrolyte) is – 0.05580C, the number of chloride(s) in the coordination sphere of the
complex is
[K???? of water = 1.86 K kg mol⁻¹]
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Given:
If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex(which behaves as a strong electrolyte) is – 0.05580C
To find:
The number of chloride(s) in the coordination sphere of the complex is
Solution:
From given, we have,
a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex(which behaves as a strong electrolyte) is – 0.05580C
Kf of water = 1.86 K kg mol⁻¹
Δ Tf = 0.0558 °C
m = 0.01
For a strong electrolyte i = n
where, n = number of ions
we use the formula,
Δ Tf = i Kf m
⇒ i = Δ Tf / Kf × m
⇒ i = 0.0558/(1.86 × 0.01)
∴ i = 3
⇒ i = n = 3
[Co(NH₃)₅Cl]Cl₂ with the number of chlorides 3 is the correct answer
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