Question

if the frequency of an object in uniform circular motion is doubled, its acceleration becomes
(1) Two times
(2) Four times
(3) Half
(4) One fourth​

Answer 1

Answer:

Acceleration becomes four times.So option (iv) is correct.

Explanation:

Since in uniform circular motion we have centripetal accelaeration $a=\frac{v^{2} }{r}$....................(i)

We know that v=rω

So,$a= \frac{r^{2} \varpi ^{2} }{r}$

$a=r\varpi^{2}$

we also know ω=2πf where f=frequency, ω=angular frequency

So, acceleration $a=4\pi ^{2}rf^{2}$

So acceleration is directly proportional to square of the frequency.

Since it is given that if the frequency of an object in uniform circular motion is doubled then,

Acceleration becomes four times.

Answer 2

Answer is 4 times.

Main formula used are:

a = v²/r

v = rw

w = 2πf

Refer attachment