If the frequency of incident light falling on a photosensitive material is double then the kinetic energy of the emitted photoelectron will be
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If the frequency of incident light falling on a photosensitive material is doubled than the kinetic energy will have the value more than double of the initial kinetic energy.
Here's how..
Using einstein photoelectric equation: hv = w + KE
here h = plank's constant
v = frequency
w = work function
KE = kinetic energy
KE = hv - w
when frequency is doubled,
KE' = 2hv - w
KE' = 2(hv-w) + w
KE' = 2KE + w
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