Question

If the function f is defined by f(x) = $\left \{ {{x + 2; if x \ \textgreater \ 1} \atop {2; -1 \leq x \leq 1}} \atop {x - 1; -3 \ \textless \ x \ \textless \ -1}} \right.$
then find the values of
i. f(3)
ii. f(0)
iii. f(-1.5)
iv. f(2) + f (-2)
v. f(-5)

Answer 1

Answer:

See the attachment.

Step-by-step explanation:

In the attachment I have answered this problem.

I hope this answer helps you

Answer 2

Answer:

(i) 5, (ii) 2, (iii) -2.5 (iv) 1 (v) Not defined.

Step-by-step explanation:

Given:

(i) f(3) : x > 1

= x + 2

= 3 + 2

= 5.

(ii) f(0) : -1 ≤ x ≤ 1

= 2

(iii) f(-1.5) : -3 < x < -1

= x - 1

= -1.5 - 1

= -2.5

(iv) f(2) + f(-2) : -1 ≤ x ≤ 1 , - 3 < x < -1.

= (x + 2) + (x - 1)

= (2 + 2) + (-2 - 1)

= 4 - 3

= 1.

(v) f(-5) :

Not defined.

Hope it helps!