Question

if the g is the acceleration due to gravity on the surface of earth its value at a height equal to is double the radius of earth​

Answer 1

ANSWER

Acceleration due to gravity at a height h from the surface of the earth

$ g'=g\frac{1}{\left(1+\frac{h}{R}\right)^2} $

Given h=2R

$ \therefore $ $ g'=g\frac{1}{(1+2)^2} $

or $ g'=\frac{g}{9} $