Question

If the given equation has real and distinct roots , then x^2+4x+k=0

Answer 1

Answer:

k = 3

Step-by-step explanation:

The quadratic equation ax² + bx + c = 0 has two real and distinct (different) roots, if discriminant D = b² - 4ac is greater than zero.

x² + 4x + k = 0

D = 4² - 4×1×k > 0

16 - 4k > 0

16 > 4k

k < 4

$x_{1}$ + $x_{2}$ = - 4

$x_{1}$ × $x_{2}$ = k

$x_{1}$ = - 3

$x_{2}$ = - 1

k = 3