Question

If the given figure ∆A=80° and the bisectors to interior angles ∆B and ∆ C meet at 'o' then ∆BOC
plz tell me the correct answer plz​

Answer 1

Answer:

In Triangle ABC:

Sum of all the interior angles=180

angle A+angle B+angle C=180

dividing both sides of equation by 2

angle A/2+angle B/2 +angle C/2=90

=>(80/2)+angle B/2 +angle C/2=90

=>angle B/2 +angle C/2=90–40=50

Sonce interior angle divider of angle B and angle C meet at O,

=>angle OCB+angle OBC=50…………………(1)

Now in triangle OBC:

angle OCB+angle OBC+angle BOC=180

using equation (1)

=>50+angle BOC=180

=>angle BOC=130