Question

if the given figure,if PQR=45,then prove than OP1OR​

Answer 1

Step-by-step explanation:

construct PN perpendicular to QR

in triangle PNQ,

angle Q=45

so QN=PN

RHS=PQ²+QR²-4*

areaPQR

=PN²+QN²+(QN+NR)²-4*0.5*QR*PN

=2PN²+PN²+NR²+2*PN*NR-2*QR*PN

=2PN²+PR²+2PN.NR-2(PN+NR)*PN

=2PN²-2PN²+2PN*NR-2PN*NR+PR²

=PR²=LHS

proved

Answer 2

Answer:

hey dear ....

in ∆ pqr, construct PN perpendicular to QR

in ∆ pqr, construct PN perpendicular to QRin triangle PNQ, angle Q=45

so QN=PN

PQ^2+QR^2-4*areaPQR=PN^2+QN^2+(QN+NR)2-4*0.5*QR*PN

=2PN^2+PN^2+NR^2+2*PN*NR-2*QR*PN

=2PN^2+PR^2+2PN.NR-2(PN+NR)*PN

=2PN^2-2PN^2+2PN*NR-2PN*NR+PR^2

=PR^2

hope it's helpful for you..