If the given two numbers are respectively 10% and 25% of third one. Find what percentage is the first of the second?
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Explanation:
Two numbers are respectively 10% and 25% more than a third number. What percent is the first number of the second?
Let “x”, “y”, and “z” be the three numbers which are related to each other as given in the problem question.
Then, “x” is 10% more than “z” means, x = z + 10% of z.
That is, x = z + (z × 10/100).
That is, x = z + 0.1z = (1 + 0.1) × z = 1.1 × z.
Then, “y” is 25% more than “z” means, y = z + 25% of z.
That is, y = z + (z × 25/100) = (1 + 0.25) × z = 1.25 × z.
Then, part of “x” upon “y” means, x/y = (1.1 × z) / (1.25 × z) = 110/125 = (22 × 5) / (25 × 5) = 22/25 = (22/25) × 100% = 22 × (100/25)% = 22 × 4% = 88%.
That is, x = 88% of y ( ANS.)
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