Question

if the given two numbers are respectively 6% and 24% of a third number, then what percentage is the first number of the second number?​

Answer 1

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$Let \: a,b,c \: be \: the \: number.$

$a = 6\% \: of \: c = \frac{6}{100} \times c = \frac{6c}{100}$

$b = 24\% \: of \: c = \frac{24}{100} \times c = \frac{28c}{100}$

$So, then, \: \frac{a}{b} = \: \frac{6c}{24c} \times \frac{100}{100} = \frac{1}{4}$

$\frac{a}{b} \: in \: \% = \frac{1}{4} \times 100 = 25\%$

Answer 2

Given,

Two numbers are respectively 6% and 24% of a third number.

To find,

What percentage is the first number of the second number?

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Let, the third number = x

According to the data mentioned in the question,

The first number will be :

= x × 6/100

= 3x/50

And,

The second number will be :

= x × 24/100

= 6x/25

Now, we have to calculate such percentage of the second number, which is equal to the first number itself.

So,

The percentage of the second number, which is equal to the first number itself :

= 100 × (First number ÷ Second number)

= 100 × (3x/50 ÷ 6x/25)

= 100 × (3x/50 × 25/6x)

= 100 × ¼

= 25%

Which implies, first number is 25% of the second number.

(This will be considered as the final result.)

Hence, the first number is 25% of the second number.