If the graph of 2x÷ky=10,intersect y-axis at (0,2),then find k
Answers
Answered by
2
I think it is not 2x÷ky=10
Given line 2x+ky=10---(1)
Put (0 ,2) in (1)
2*0+k*2=10
2k=10
k=10/2
k=5
Given line 2x+ky=10---(1)
Put (0 ,2) in (1)
2*0+k*2=10
2k=10
k=10/2
k=5
Answered by
0
Answer:
Step-by-step explanation:
I think it is not 2x÷ky=10
Given line 2x+ky=10---(1)
Put (0 ,2) in (1)
2*0+k*2=10
2k=10
k=10/2
k=5
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