Question

If the graph of 2x+ky = 10k, intersects x-axis at (2,0) find k.

Answer 1

Answer:

The value of k is $\frac{2}{5}$

Step-by-step explanation:

Graph of 2x+ky = 10k

intersects x-axis at (2,0)

we have to find the value of K

Here substitute  x=2,y=0

$2(2)+0=10K\\10k=4\\k=\frac{4}{10}$

The value of k is $\frac{2}{5}$

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Answer 2

Step-by-step explanation:

this is the answer of this Question hope it help