if the graph of 2x+ky=10k,intersests x-axis at(2,0),then find k
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its simple u just put the values for x and the solve the resultant equation.
Answered by
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Equation : 2x + ky = 10k,
Intersests x - axis at (2,0)....
Therefore, putting x = 2 and y = 0 in the equation we get,
2(2) + k(0) = 10k
4 + 0 = 10k
4 = 10k
4/10 = k
Therefore, k = 2/5.....
Intersests x - axis at (2,0)....
Therefore, putting x = 2 and y = 0 in the equation we get,
2(2) + k(0) = 10k
4 + 0 = 10k
4 = 10k
4/10 = k
Therefore, k = 2/5.....
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