If the graph of graph of the equation 2x + 9y + (K-2) =0 passes through the origin then find the value of k.
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Answer:
it passes through the origin (0,0)so
X=0 and y=0
\begin{gathered}2 \times 0 + 9 \times 0 + (k - 2) = 0 \\ = > k = 2\end{gathered}2×0+9×0+(k−2)=0=>k=2
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Answer:
X=0 and y=0
2 \times 0 + 9 \times 0 + (k - 2) = 0 \\ = > k = 2
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