if the graph of line x+7y = k passes through the origin find the value of k.
Answers
The given equation of line is
(k−3)x−(4−k
2
)y+k
2
−7k+6=0
(a) If the given line is parallel to the x-axis, then
slope of the given line= slope of the x-axis =0
⇒
(4−k
2
)
(k−3)
=0
⇒k−3=0
⇒k=3
Thus, if the given line is parallel to the x-axis, then the value of k is 3.
(b) If the given line is parallel to the y-axis, it is vertical, hence,its slope will be undefined.
The slope of the given line is
(4−k
2
)
(k−3)
Now,
(4−k
2
)
(k−3)
is undefined at k
2
=4
⇒k=±2
Thus, if the given line is parallel to the y-axis,then the value of k is ±2.
(c), If the given line is passing through the origin, then point (0,0) satisfies the given equation of line
(k−3)(0)−(4−k
2
)(0)+k
2
−7k+6=0
⇒k
2
−7k+6=0⇒k
2
−6k−k+6=0
⇒(k−6)(k−1)=0⇒k=1 or k=6
Thus, if the given line is passing through the origin, then the value of k is either 1 or 6.
Answer:
x + 7y is k then k is origin