if the gravitational acceleration at surface of earth is 9.81m/s² what is its value at a height equal to diameter of earth from its surface ans is 1.09 plz xplain
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g = Gm/r^2
9.81= Gm/r^2 --------------(1)
g' = Gm/(3r)^2
= Gm/r^2 × 1/9
= 9.81 × 1/9 ---------------from eq (1)
= 1.09
The value of g at height 2r from surface will be 1.09 m/s^2
hope it helped,☺
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9.81= Gm/r^2 --------------(1)
g' = Gm/(3r)^2
= Gm/r^2 × 1/9
= 9.81 × 1/9 ---------------from eq (1)
= 1.09
The value of g at height 2r from surface will be 1.09 m/s^2
hope it helped,☺
plzzz mark as brainliest.......!
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