Question

If the gravitational acceleration at surface of Earth is g, then increase in potential energy in lifting an object of mass m to a height equal to half of radius of earth from surface will be
a) mgR/ 2
b) 2mR/3
c) mgR/4
d) mgR/3

Answer 1

Answer:

Option A is answer...

Let's me explain u guys...

Gravitational petential energy at r, P.E=− GMm/r

As GM=gR2 ⟹P.E=− mgR

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For r=R, P.E'=−mgR/2

Gain in P.E= P.E ′ −P.E= mgR/2