Question

if the gravitational force between a teacher weighing 68kg and a student weighing 52kg is 1.48 × 10-⁸ Nm², at what distance are they standing?​



if u answer fast I'll mark u brainliest!!!

Answer 1

Answer: 4

Explanation

F= GMm

      R^2

R= GMM

        F

6.6*10^-11*52*68  

    1.48*10^-8

R^2= 15768*10^-3

R= 4                         hopes it helps you

Answer 2

Given:-

☆Mass of the teacher(m1)=68kg

☆Mass of the student(m2)=52kg

☆Gravitational force between them(F)=1.48×10^-8N

To find:-

☆Distance between them

Solution:-

☆Value of G=6.67×10^-11 Nm²/kg²

We know from the universal law of gravitation that:-

=>F=Gm1m2/R²

=>R²=Gm1m2/F

=>R²=(6.67×10^-11×68×52)/(1.48×10^-8)

=>R²=6.67×68×52/1.48×10^(-11-(-8))

=>R²=15935.8×10^-3

=>R²=15935.8/1000

=>R²=15.9~16

=>R²=16

=>R=4m

Thus,distance between them is 4m.