if the H.C.F of 65 and 117 is expressible in the form 65m – 117, the value of m is
(a)4 (b) 2 (c) 1 (d) 3
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4
Answer:
B) 2
Explanation:
Let us find the HCF of 65 and 117,
117 = 1 × 65 + 52
65 = 1 × 52 + 13
52 = 4 ×13 + 0
therefore HCF of 65 and 117 is 13.
65m -117 = 13
65m = 117+13 = 130
m =130 / 65 =2
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The Answer is 2
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