If the H+ concentration is 0.000001 M, what is the pOH of the solution?
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Given conditions ⇒
[H⁺] = 0.000001 M = 10⁻⁶ M.
Using the Formula,
pH = - log[H⁺]
⇒ pH = -log[10⁻⁶]
∴ pH = 6log10
∴ pH = 6
Now, For pOH,
pH + pOH = 14
⇒ pOH = 14 - 6
∴ pOH = 8
Hope it helps .
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