If the half-life for decomposition of a drug is 9
hrs, how long will it take for 125mg of the drug
to decompose by 28%? Assume first-order
kinetics.
Answers
Answered by
1
Answer:
4.2 hrs time required to complete 28% reaction
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Answered by
0
Answer:
Given: Half life (T
1/2
)=120 minutes
For 1st order reaction, Half life (T
1/2
)=
rateconstant(K)
0.693
Here, K=
120
0.693
=0.00578min
−1
Let initial concentration a mol and time t in minutes required for 90% decomposition of the compound
Now, t=
K
2.303
log
a−0.9a
a
=
0.00578
2.303
log10=398 minutes
Thus, 398 minutes are required for 90% decomposition of the compound.
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