If the half life of a first order reaction in A is 12 min how long it will take to reach 25% of its initial conc:10%of it's initial cone????
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Answered by
0
Answer:
Half life period t
1/2
of a reaction is defined as the time required to reduced the concentration of a reactant to one half of its initial value.
k
1
=
t
2.303
log(
a−x
a
)
if amount reacted x=
2
a
then t=t
1/1
∴t
1/2
=
t
2.303
log(
a−a/2
a
)
t
1/2
=
k
1
2.303log(2.0)
⇒t
1/2
=
k
1
0.693
secs
Thus half life period of a first order reaction is independent of the initial concentration of the reactant.
Explanation:
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Explanation:
see formula in pic.
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