Question

. If the Half Life of a radioactive substance of 600 grammes is 2 days, what would be the amount of mass in 6 days?

Answer 1

Answer:

75 g of substance will remain after 6 days.

Explanation:

No = 600 g                 N is concentration at time T

n = T /T1/2                   No is initial cincentration

  = 6 /2 = 3                   T is time

$\frac{N}{No} =[ \frac{1}{2} ]^{n}$                      T1/2 is half life

     = 1/8                         n is constant

N /No = 1 /8

8 N = No

N = 600 /8

   = 75 g