If the half life of the first order reaction is 50s , whatwill be the value of its rate constant
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Answer:
1.3 × 10^-2 sec^-1
Explanation:
t1/2 = 0.693/k
k= 0.693/50
=1.3 × 10^-2
Answered by
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k= 0.693/t1/2
= 0.693/ 50
= 1.38×10-² s-¹
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