if the half life period of a first order reaction is 2.31 into 10 to the power 3 minutes how long will it take for 1/5 of the reactant to be left Behind given log 5 equal to 0.6 990
Answers
Answered by
4
5.36 into 10 power 3
Answered by
1
Answer:
5.36×10³
=5360 is correct answer
Similar questions