If the HCF (210,55) is expressible in the form of 210 × 5 - 55y, find y
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Hey dear !
Here's your answer ❗
Let us Frist the HCF of 210 and 55.
Applying Euclid devision lemma on 210 and 55, we get
210 = 55 × 3 + 45
55 = 45 × 1 + 10
45 = 4 × 10 + 5
10 = 5 × 2 + 0
we observe that the remainder at this stage is zero. so, the last division i.e., 5 is the HCF of 210 and 55.
∴ 5 = 210 × 5 + 55y
= 55y = 5 - 1050
= -1045
∴ y = -19
h
glad help you
it helps you
thank you ☺
@vaibhavhoax
Here's your answer ❗
Let us Frist the HCF of 210 and 55.
Applying Euclid devision lemma on 210 and 55, we get
210 = 55 × 3 + 45
55 = 45 × 1 + 10
45 = 4 × 10 + 5
10 = 5 × 2 + 0
we observe that the remainder at this stage is zero. so, the last division i.e., 5 is the HCF of 210 and 55.
∴ 5 = 210 × 5 + 55y
= 55y = 5 - 1050
= -1045
∴ y = -19
h
glad help you
it helps you
thank you ☺
@vaibhavhoax
Answered by
9
This is your complete answer and right answer
plse mark it as brainlist
plse mark it as brainlist
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