if the hcf ( 210,55) is expressiblw in the form of 210×5 -55y. find y
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hcf(210,55)=5
210×5-55y=5
then
y=210/11
210×5-55y=5
then
y=210/11
Answered by
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HCF (210,55) = 5
210×5-55y=5
5-55y=5/210=45
-55y =45-5=40
y=-8/11.
210×5-55y=5
5-55y=5/210=45
-55y =45-5=40
y=-8/11.
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