Question

If the HCF(6, p) = 2 and LCM of(6, p) = 60, find p.​

Answer 1

$\large\underline{\sf{Solution-}}$

It is provided that,

HCF (6, p) = 2

LCM (6, p) = 60

We know, From real number system

If a and b are two positive integers, then

Product of 2 numbers = HCF (a, b) × LCM (a, b)

So, we have

a = 6

b = p

HCF = 2

LCM = 60

Therefore, a × b = HCF × LCM

So, 6 × p = 2 × 60

This implies, p = 20

More to know,

1. HCF always LCM

2. HCF of two numbers is always smaller or equals to one of two positive integers a and b.

Answer 2

Answer:

HCF×LCM= product of two numbers

2×60=6×p

120=6p

p=120÷6

p=20