Question

If the HCF and LCM of two numbers are 12 and 180 and one of the numbers is 36 ben find the other number​

Answer 1

Answer:

• 60

Step-by-step explanation:

• HCF X LCM = Product of 2 numbers
• 12 X 180 = 36 X K
• K = (12 X 180) / 36
• K = 180/3 = 60

Answer 2

${\mathbf {\blue{S}{\underline{\underline{olution:-}}}}}$

$\mathfrak{\underline{AnswEr:-}}$

• The other required number = 60

$\mathfrak{\underline{Given:-}}$

• If the HCF and LCM of two numbers are 12 and 180 and one of the numbers is 36.

$\mathfrak{\underline{Need\:To\: Find:-}}$

• The other required number = ?

${\mathbf {\blue{E}{\underline{\underline{xplanation:-}}}}}$

Let the other required number be y.

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\bigstar{\underline{\boxed{\sf\purple{Products \:of\: number = HCF \times LCM}}}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {36 \times y = 12 \times 180}$

$\longrightarrow \sf {36y = 2160}$

$\longrightarrow \sf {y = \cancel\dfrac{2160}{36} }$

$\longrightarrow{\gray{ \underbrace{\boxed{\underline{\underline{\blue{ \tt y = 60 }}}}}}}$

$\:\:\:\:\dag\bf{\underline{\underline \pink{Hence:-}}}$

• The other required number is 60.

$\rule{200}{2}$