Question

if the HCF and the LCM of x and 20 are 2 and 60 respectively the value of x will b​

Answer 1

Answer:

Step-by-step explanation:HCF=(x+2),LCM=(x+2)  

2

(x−2)

HCF

LCM

​  

=  

(x+2)

(x+2)  

2

(x−2)

​  

=(x+2)(x−2)

The required expressions are (x+2)(x+2) and (x+2) (x-2), i.e., (x+2)  

2

 and (x  

2

−4).

Answer 2

Answer:

this is the appropriate answer of this question