If the HCF of 144 and 90 is expressible in the form of 144x +90y, then value of x - y =?
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hey friend
hcf of both no
144 = 2×2×2×2×3×3
90 = 2×3×3×5
hcf = 2×3×3 (common factors) = 18
144x +90y = 18
x/ 8 + y/ 5 = 1
we have 1 equation and 2 variable ..
put diffrent value of x .. we can get diffrent value for y ..
ex
(x ,y) = ( 16 , -5)
(x, y) = ( 24, -10)
...
same as infinite solutions
for above equation no particular solution available.
hope it will help you !!
hcf of both no
144 = 2×2×2×2×3×3
90 = 2×3×3×5
hcf = 2×3×3 (common factors) = 18
144x +90y = 18
x/ 8 + y/ 5 = 1
we have 1 equation and 2 variable ..
put diffrent value of x .. we can get diffrent value for y ..
ex
(x ,y) = ( 16 , -5)
(x, y) = ( 24, -10)
...
same as infinite solutions
for above equation no particular solution available.
hope it will help you !!
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