Question

If the hcf of 152 and 272 is expressible in the form 272x+152y find x and y

Answer 1

Answer:

x + y =272+ 152

the

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Answer 2

152 = 2*2*2*19

272 =2*2*2*2*17

so hcf is 2*2*2=8

now 8=272y+152x

since a= bq+r

or 272=152*1+(272-152)=152+120

now

272*8+152x=hcf

or 2176+152x=8

or x= -2168/152= -271/19

so 8= 272*8+152*(-271/19)

so x=(-271/19) and y=8

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